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2020-06-01

226. Invert Binary Tree

Question:

Invert a binary tree.

Example 1:

     4
   /   \
  2     7
 / \   / \
1   3 6   9

Example 2:

     4
   /   \
  7     2
 / \   / \
9   6 3   1

Trivia:
This problem was inspired by this original tweet by Max Howell:

Google: 90% of our engineers use the software you wrote (Homebrew), but you can’t invert a binary tree on a whiteboard so f*** off.


Solution:

Using DFS to traverse the tree (Preorder traversal).

/**
 * Definition for a binary tree node.
 * public class TreeNode {
 *     int val;
 *     TreeNode left;
 *     TreeNode right;
 *     TreeNode() {}
 *     TreeNode(int val) { this.val = val; }
 *     TreeNode(int val, TreeNode left, TreeNode right) {
 *         this.val = val;
 *         this.left = left;
 *         this.right = right;
 *     }
 * }
 */
class Solution {
    public TreeNode invertTree(TreeNode root) {
        if (root == null) return null;
        
        TreeNode temp = root.left;
        root.left = root.right;
        root.right = temp;
        
        invertTree(root.left);
        invertTree(root.right);
        
        return root;
    }
}